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poizon [28]
3 years ago
10

-5/8 - 2/7 (fraction form only) P.S. help me please :)

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
Here is a picture of the answer:

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Im 90% sure its 9546745 females

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(a) How many different three-letter initials can people have: , (b) How many different three-letter initials with none of the le
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write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 40 to 56
masha68 [24]

Answer:

  5/7

Step-by-step explanation:

A common factor of 8 can be canceled from numerator and denominator.

  40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7

_____

Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.

__

If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...

  56 ÷ 40 = 1 r 16

  40 ÷ 16 = 2 r 8

  16 ÷ 8 = 2 r 0 . . . . . the zero remainder signals that the divisor (8) is the GCD

Now, your fraction is ...

  (40/8) / (56/8) = 5/7

3 0
3 years ago
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Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]
madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

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2 years ago
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