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3 years ago

5 The width of this rectangle is of the length. Find the

Mathematics

1 answer:

LenKa [72]3 years ago

8 0

Answer:

4 in.

Step-by-step explanation:

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a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be

ElenaW [278]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Let the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

$\rightarrow$ Now, clearly it is forming a triangle.

So, in triangle ABC,

$\rightarrow$ $\sf{Tan50° \:= \: \frac{BC}{AC}}$

$\rightarrow$ $\sf{1.19 \:= \: \frac{BC}{50}}$

$\rightarrow$ $\sf{1.19 ×50\:= \: BC}$

$\rightarrow$ $\sf{59.5m\:= \: BC}$

$\rightarrow$ Hence, BC = 59.5m

So, BD(total height of the tower) $\sf{ = \:BC+CD}$

$\sf{= \:59.5+1.65}$

$\sf{=\: 61.15m}$

Therefore, total height of the tower = $\sf\purple{ 61.15m.}$

________________________________

Hope it helps you:)

5 0

2 years ago

Read 2 more answers

One cube has a volume of 192 cm3, and another has a volume of 375 cm3. How much longer is the edge of the larger cube than that

vesna_86 [32]

Answer:

134

Step-by-step explanation:

5 0

3 years ago

Choose one of the factors of 1331x3 − 8y3.

daser333 [38]

B is the answer hope this helps :)

7 0

3 years ago

Read 2 more answers

Help me asap!!!! please

Lubov Fominskaja [6]

Answer:

x = 3 should be the answer

Step-by-step explanation:

y is not graphed so y isn't part of the equation while x is so its X = K (K being the number that it goes up on) same thing applies to y if its horizontal then the equation is Y = K)

6 0

2 years ago

Match its group with its percentage or mean Using

krok68 [10]

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10

7 0

3 years ago