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Svetradugi [14.3K]
3 years ago
13

1. Solve MMXXVII -MCMXCIIA.LVB. XLVC. XXXVD. XXVE. XV​

Mathematics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

the answer is C. XXXV

Step-by-step explanation:

MMXXVII -MCMXCII= XXXV

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A car was bought in 2009 for $120000. it 2016 it value decrease by 20%. it's value decrease by 10% of it's value in 2010.fond th
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Answer:

<h2>This is the case % decrease</h2><h2>120000*80/100*90/100</h2><h2>=12*80*90</h2><h2>=7200*12</h2><h2>=72000+ 14400</h2><h2>=86400 rs</h2>

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0.933333 as a fraction show work
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Answer:

84/90

Step-by-step explanation:

Let 0.9333....... be x.

10x = 9.3333....... & 100x = 93.33333.......

So,

=> 100x - 10x = 93.33333...... - 9.333333.....

=> 90x = 84

=> x = 84/90

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A transformation is shown in the diagram. ∠A  ∠A' and ∠C ∠C' Which transformation is shown in the figure? ΔABC was dilated to fo
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the correct option is C

Step-by-step explanation:

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Can anyone help me with these 2 queen
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1st is yes

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Blake is playing a racing game on his computer. The game tracks the locations of objects using and y coordinates (see graph belo
Anvisha [2.4K]
<h3>Answer: 2.2 units</h3>

============================================

Explanation:

I'll define these point labels

  • B = Blake's starting position
  • F = finish line
  • C = the third unmarked point of the triangle

The locations of the points are

  • B = (-8,1)
  • C = (-6,-3)
  • F = (4,-2)

Use the distance formula to find the distance from B to C

B = (x_1,y_1) = (-8,1) \text{ and } C = (x_2,y_2) = (-6,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-8-(-6))^2 + (1-(-3))^2}\\\\d = \sqrt{(-8+6)^2 + (1+3)^2}\\\\d = \sqrt{(-2)^2 + (4)^2}\\\\d = \sqrt{4 + 16}\\\\d = \sqrt{20} \ \text{ ... exact distance}\\\\d \approx 4.47214 \ \ \text{... approximate distance}\\\\

Segment BC is roughly 4.47214 units long.

Following similar steps, you should find that segment CF is approximately 10.04988 units long.

If Blake doesn't take the shortcut, then he travels approximately BC+CF = 4.47214+10.04988 = 14.52202 units. This is the path from B to C to F in that order.

---------

Use the distance formula again to find the distance from B to F. This distance is about 12.36932 units. He travels this amount if he takes the shortcut.

Subtract this and the previous result we got

14.52202 - 12.36932 = 2.1527

That rounds to 2.2

This is the amount of distance he doesn't have to travel when he takes the shortcut.

In other words, the track is roughly 2.2 units shorter when taking the shortcut.

Side note: Replace "units" with whatever units you're working with (eg: feet or meters).

7 0
2 years ago
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