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4 years ago

Simplify the expression attached. a | 8 b | 10 c | 16 d | 22

Mathematics

1 answer:

Dmitry_Shevchenko [17]4 years ago

4 0

We need to follow PEMDAS

$\frac{8+ 3 \times 4}{2} = \frac{8+12}{2} = \frac{20}{2} =10$

The answer is B.

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The shorter leg of a right triangle is 7cm shorter than the longer leg. The hypotenuse is 7cm longer then the linger leg. What i

Gelneren [198K]

The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.

Step-by-step explanation:

Let,

The longer leg = x

The shorter leg = x-7

Hypotenuse = x+7

Using Pythagoras theorem;

$a^2+b^2=c^2\\(x-7)^2+(x)^2=(x+7)^2\\x^2-14x+49+x^2=x^2+14x+49\\2x^2-14x+49-x^2-14x-49=0\\x^2-28x=0\\x(x-28)=0\\$

Either,

x= 0

Or,

x-28=0 =>x=28

As length cannot be zero, therefore,

Longer side = 28cm

Shorter side = x-7 = 28-7 = 21cm

Hypotenuse = x+7 = 28+7 = 35cm

The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.

Keywords: triangle, pythagoras theorem

Learn more about triangles at:

#LearnwithBrainly

5 0

4 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

3 years ago

A computer scans every 2.75 days and another scans every 3.5 days

Brut [27]

Answer:

Alright, so we have to find the LCM of 2.75 and 3.5.

A good start would be to multiply them together to get 9.625, but we want a whole day!

This would be every 77 days :)

5 0

3 years ago

erastovalidia [21]

Answer:

D.) 4x + y

Step-by-step explanation:

3x + x + y

Add 3 x and x .

4 x + y

7 0

3 years ago

Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(1). 2 8 10 4

Klio2033 [76]

Hello!

You can solve this by plugging 1 into $g(x)$ and plugging the result into $h(x)$ .

$g(x) = 2x$
$g(1) = 2(1)$
$g(1) = 2$

$h(x) = 2x + 4$
$h(g(1)) = 2(2) + 4$
$h(g(1)) = 4 + 4$
$h(g(1)) = 8$

Answer:
<span>(h ∘ g)(1) = 8</span>

8 0

3 years ago