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tresset_1 [31]
2 years ago
8

How many child tickets were sold that day?

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
3 0

\huge\boxed{\fcolorbox{black}{red}{Answer}}

first let's name a couples of variable

• the number of adults tickets sold: a

• the number of children tickets sold: c

From the problem we know

a + c = 128

and

$5.40c + $9.20a = $976.20

1) solve the equation to alpha

a+c-c = 128 -c

a+0=128-c

a=128-c

2) substitute (128 - c) for a in the second equation and solve to c

$5.40c + $9.20a = $976.20 become

$5.40c + $9.20(128 - c) = $976.20

$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20

$5.40c - $9.20c + $ 1177.6 = $976.20

($5.40 - $9.20)c +$1177.6 = $976.20

-$3.80c + $1177.6 = $9.76.20

-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60

-$8.30c + 0 = $201.40

-$3.80c = - $201.40

-$3.80c. -$201.40

________. = _________

-$3.80. -$3.80

-$3.80c. -$201.40

________. = _________. - they are 4 cut the no

-$3.80. -$3.80

c = $201.40

________

3.80

c = 53

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Say a point P(x, y) moves up or down ' k ' units, then we can represent that transformation by adding or subtracting respectively 'k' unit to the y-coordinate of the point P.

In the same way if P(x, y) moves right or left ' h ' units, then we can represent that transformation by adding or subtracting respectively 'h' units to the x-coordinate.

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Applying the concept:

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The transformation that maps ABCD onto its image is translation given by (x + 5, y + 2),

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see below

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Step-by-step explanation:

The question is asking us how much each pair of socks cost. With the information we are given, we know that there are 5 pairs and that they all cost the same amount. If the total were just the 5 socks, we could easily divide the total by 5 to get the price of each pair but that's not the case. The soccer ball is included in the final cost. To overcome this, we just have to subtract the soccer ball's cost ($45) from the total.

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Simpler Explanation:

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