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2 years ago

How to turn -2/3 into y+mx+b

Mathematics

2 answers:

professor190 [17]2 years ago

6 0

Answer: The slope-intercept form is y=mx+b y = m x + b , where m is the slope and b is the y-intercept.

andrew11 [14]2 years ago

3 0

Answer:

y=-2/3x

Step-by-step explanation:

y=mx+b the m is your slope and the b is your y-intercept, assuming that -2/3 is your slope and you have no y-int, you simply apply it to the formula replacing m giving us the result of y=-2/3x! hope this helped :-)

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An angle measures 30° more than the measure of its supplementary angle. What is the measure of each angle?

yarga [219]

Hi there!
$\boxed{\angle A = 75^o, \angle B = 105^o}$

Let there be two angles, ∠A and ∠B, that are supplementary to each other. Therefore:

∠A + ∠B = 180°

We can assign ∠B to be the greater angle. Assume ∠A has a measure of x°.

∠A = x°

∠B = x° + 30°

The sum is equal to 180°, so:

x° + (x° + 30°) = 180°

Solve for x°.

2x° + 30° = 180°

2x° = 150°

x° = 75°

Thus, ∠A = 75°.

Since ∠B is 30°, greater:
∠B = 75° + 30° = 105°.

4 0

1 year ago

Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)

Sati [7]

Answer:

(2,1)

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)$

8 0

3 years ago

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D = 8 cm<br> h = 18 cm<br> What is the surface area of the cylinder

mars1129 [50]

Answer:

144 (If multiplying)

Step-by-step explanation:

18x8=144.

5 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

(Once again) "find the value of x"

alukav5142 [94]

Answer:

Step-by-step explanation:

8 0

3 years ago

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