Answer:
what do you need help with exactly?
Step-by-step explanation:
Answer:
JL ≈ 32
Step-by-step explanation:
The triangle JKL has a side of JK = 24 and we are asked to find side JL. The triangle JKL is a right angle triangle.
Let us find side the angle J first from the triangle JKM. Angle JMN is 90°(angle on a straight line).
using the cosine ratio
cos J = adjacent/hypotenuse
cos J = 18/24
cos J = 0.75
J = cos⁻¹ 0.75
J = 41.4096221093
J ≈ 41.41°
Let us find the third angle L of the triangle JKL .Sum of angle in a triangle = 180°. Therefore, 180 - 41.41 - 90 = 48.59
Angle L = 48.59
°.
Using sine ratio
sin 48.59
° = opposite/hypotenuse
sin 48.59
° = 24/JL
cross multiply
JL sin 48.59
° = 24
divide both sides by sin 48.59
°
JL = 24/sin 48.59
°
JL = 24/0.74999563751
JL = 32.0001861339
JL ≈ 32
A Pattern constitutes a set of numbers or objects in which all the members are related with each other by a specific rule.
A rhombus is a shape with four congruent sides but its angles are not congruent.
Answer:
- 280 student tickets
- 520 adult tickets
Step-by-step explanation:
You may recognize that you are given two relationships between two unknowns. You can write equations for that.
You are asked for numbers of adult tickets and of student tickets. It often works well to let the values you're asked for be represented by variables. We can choose "a" for the number of adult tickets, and "s" for the number of student tickets. Then the problem statement tells us the relationships ...
a + s = 800 . . . . . . 800 tickets were sold
12.50a + 7.50s = 8600 . . . . . . . revenue from sales was 8600
(You are supposed to know that the revenue from selling "a" adult tickets is found by multiplying the ticket price by the number of tickets: 12.50a.)
___
You can solve these two equations any number of ways. One way is to do it by <em>elimination</em>. We can multiply the first equation by 12.50 and subtract the second equation:
12.50(a +s) -(12.50a +7.50s) = 12.50(800) -(8600)
5s = 1400 . . . . simplify. (The "a" variable has been eliminated.)
s = 280 . . . . . . divide by 5
Then the number of adult tickets can be found from the first equation:
a + 280 = 800
a = 520
280 student tickets and 520 adult tickets were sold.
