The 3-D shape would be created if the figure was rotated around the x-axis is a cone
<h3>What are 3-D shapes?</h3>
3-D shapes (short form of 3-Dimensional shapes) are shapes that have width, length and height
<h3>How to determine the 3-D shape?</h3>
The coordinates are given as:
(0, 0), (-3, -4) and (-3, 0)
When the above coordinates are plotted on a coordinate plane and the points are connected;
We can see that the points form a right-triangle
See attachment for the shape
As a general rule
Rotating a right-triangle across the x-axis would form a cone
Hence, the 3-D shape would be created if the figure was rotated around the x-axis is a cone
Read more about rotation at:
brainly.com/question/4289712
#SPJ1
Given that Audra was drawing a perpendicular bisector of segment AB with a compass. She started with line segment AB. Then, she placed her compass point on A and opened the compass more halfway to B.
Her next step will be "Using the width of the compass from the previous step, draw two arcs to the left and right of both A and B".
Answer:
When x = -2, y = 3
When x = -1, y = 0
When x = 0, y = -3
When x = 1, y = -6
Step-by-step explanation:
Given:
y = -3x - 3
Fill in the table using the following value for x
When x = -2
y = -3x - 3
y = -3(-2) - 3
y = 6 - 3
y = 3
When x = -2, y = 3
When x = -1
y = -3x - 3
y = -3(-1) - 3
y = 3 - 3
y = 0
When x = -1, y = 0
When x = 0
y = -3x - 3
y = -3(0) - 3
y = 0 - 3
y = -3
When x = 0, y = -3
When x = 1
y = -3x - 3
y = -3(1) - 3
y = -3 - 3
y = -6
When x = 1, y = -6
if your asking for the equation, it's t + 7 < 3
The volume, surface area and the ratios of the SA to volume will be as follows:
Volume=πr²h
Area=2πr²+πdh
Ratio of SA to volume=Area/volume
π=3.14
Thus using the above formula:
1.
a]
Radius: 3 inches
Height: 2 inches
Volume=πr²h
volume=π×3²×2=56.52 in³
b]
Area=2πr²+πdh
2×π×3²+π×2×3×2
=56.55+37.68
=94.23 in²
c]
Ratio=area/volume
=94.23/56.52
=1.6672
1.
Radius: 2 inches
Height: 9 inches
a]
V=πr²h
V=3.14*2^2*9
V=113.04 in³
b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*2*2*9
=25.12+113.04
=138.16 in²
c]
Ratio=area/volume
=138.16/113.04
=11/9
3.
Diameter=4 inches
Height= 9 inches
a]
V=πr²h
V=3.14×2²×9
V=113.04
b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*4*9
=25.12+113.04
=138.16 in²
c]
Ratio=area/volume
=138.16/113.04
=11/9
4]
Diameter: 6 inches
Height: 4 inches
a]
Volume=πr²h
=3.14×3²×4
=113.04 in³
b]
Area=2πr²+πdh
=2×3.14×3²+3.14×6×4
=56.52+75.36
=131.88 in²
c] Ratio
131.88/113.04
=7/6
1. For the surface area to volume to be small it means that the area is smaller than the volume, for surface area to volume be larger it means that the surface area is larger than the volume. It is more economical for the surface area to volume to be small because it will mean that small amount of materials make cans with large volume. This means cost of production is cheaper.
2. To evaluate this process let's use one of the dimensions:
Radius: 3 inches
Height: 2 inches:
i. add radius and height:
3+2=5 inches
ii. Multiply radius and height:
3×2=6
iii. Dividing the result from step 1 by the result in step 2:
5/6
iv. Multiply the result from step 3 by 2:
5/6×6
=5
This result does not seem to add up to the result in our earlier ratio. Thus we conclude that Khianna was wrong. This method can't work with 3-D figures.
