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3 years ago

PLEASE HELP ASAP. I WILL GIVE BRAINLIEST

Mathematics

1 answer:

serg [7]3 years ago

3 0

Answer:

because if you divide or multiply it makes that negative or multiple sign bigger so it would flip

Step-by-step explanation:

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NEED HELP ASAP...

crimeas [40]

1) The dependent variable is the total cost.
2) The perimeter is 36 inches.

The dependent variable is the one that gets changed by the other one. In this case, the total cost gets changed by the amount of fabric bought.

To find the perimeter:

Since the ratios of the side length to perimeter is the same, we set up the ratio:
2/8 = 9/x

Cross multiply:
2*x = 8*9
2x = 72

Divide both sides by 2:
2x/2 = 72/2
x = 36

3 0

3 years ago

If Michael's family has 210 acres and each cow take 1/3 acre for grazing, how many cattle could their farmland support?

Semenov [28]

630 acres

Since 1 cow takes $\frac{1}{3}$ of an acre for grazing that means you can have 3 cattle per acre so simply do 210×3 to get 630

3 0

4 years ago

Read 2 more answers

What is the perimeter of the square if it's 4√5

Brut [27]

im pretty sure its 8.94

7 0

3 years ago

1) Veja o calendário de plantio e colheita do Arroz na região Centro-Oeste do Brasil . *

alexgriva [62]

Answer:

sos, i dont understand

Step-by-step explanation:

6 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago