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DENIUS [597]
3 years ago
13

What is the equation of the line shown in this graph? The points are (-2, 2) and (-2, -3)

Mathematics
1 answer:
KengaRu [80]3 years ago
5 0

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-2}{-2-(-2)}\implies \cfrac{-3-2}{-2+2}\implies \stackrel{und efined}{\cfrac{-5}{0}}


so our slope is undefined, that means a vertical line, check the picture below

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Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
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the answer is the option <span>B.)
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6 0
3 years ago
Read 2 more answers
I need working out and answers for the following:
LenaWriter [7]
A. 4x - 3 = 2x + 7
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C. 2( x + 3) = x - 4
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D.4 ( 5x - 2) = 2( 9x + 3)
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2x = 14
x = 7

E.4x - 1/2 = x - 7
4x - x = -7 + 1/2
3x = (-14 + 1)/2
3x = -13/2
x = -13/6

F. 3x + 2 = 2x + 13/3
3x - 2x = 13/3 - 2
x = (13 - 6)/3
x = 7/3


Hope This Helps You!
4 0
3 years ago
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Brrunno [24]
The total number of ribbons is 8 because 4 + 3 + 1 is 8
The number of green ribbons is 3
That means that 3 out of the 8 ribbons are green
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Evaluate. 12+4⋅3−15 Enter your answer in the box.
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Answer:

the answer is 1.3

Step-by-step explanation:

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