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3 years ago

What is the equation of the line shown in this graph? The points are (-2, 2) and (-2, -3)

Mathematics

1 answer:

KengaRu [80]3 years ago

5 0

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-2}{-2-(-2)}\implies \cfrac{-3-2}{-2+2}\implies \stackrel{und efined}{\cfrac{-5}{0}}$

so our slope is undefined, that means a vertical line, check the picture below

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How many 3/4s are in 6

Pepsi [2]

Hey there!
Let's first find an easier situation.
If we're saying:
How many fives are in ten?
We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
6 divided by 3/4
=
6 * 4/3
= 24/3
= 8 3/4's in 6.

Hope this helps!

7 0

3 years ago

In which quadrant of the coordinate graph does point J lie?

tia_tia [17]

J lies in Quadrant II.

7 0

2 years ago

Read 2 more answers

Jennifer's saving to buy a bike. The bike costs $245. She has $125 saved, and each week she adds $15 to her savings. How long wi

Novosadov [1.4K]

It will take her 8 weeks to save up enough money for the bike.

To get the answer first you have to subtract 125 from 245 to see how much money she still has to save then divide the answer which is 120 by 15 and you get 8. Hope this helps!!

4 0

2 years ago

Read 2 more answers

Help solve this I’m not sure if my answer was right. Pythagorean theorem.

Ganezh [65]

Answer:

C. since 8, 15, 17 are pythagorean triples

8 0

3 years ago

1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o

lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

$SD = \sqrt{E(X^{2}) - (E(X))^{2} }$

E(X²) = (6/19)*5² - (13/19)*2²

E(X²) = 5.158

$SD = \sqrt{5.158 - 0.209^2}$

SD = 2.26

c) probability that, in total, the gambler wins at least $1.

P(X >1)

$z = \frac{X - \mu}{\sigma}$

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0

3 years ago