The direction given by Enzo's sister is an illustration of distance
Enzo's distance from the east of 1st avenue to the field is 6 miles
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How to describe the directions?</h3>
From the question, we have the following directions:
- Start at east of 1st avenue
- Drive 3 miles
- Make a 90 degrees right turn
- Drive 1 mile
- Turn at 90 degrees intersection
- Drive 2 miles
The above directions imply that the total distance from the east of 1st avenue to the field is:
Distance = 3 miles + 1 mile + 2 miles
Evaluate the sum
Distance = 6 miles
Hence, Enzo's distance from the east of 1st avenue to the field is 6 miles
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BD = AC Given. BD cuts AC in half. That's what bisectors do.
BD = BD Reflexive property of a line (it is always equal to itself).
<ADB = <ADC = 90o
DB is perpendicular to AC Given.
<ADB + <ADC = 180o The two are supplementary.
Each angle = 90o Perpendicular means that one line meets another at 90o
2x = 180
x = 90o
Since each of the enclosed angles = 90, two have two triangles congruent by SAS <<<< Answer
Answer:
The speed in still water is 5 miles per hour.
Step-by-step explanation:
distance with current = 90 miles
distance against current = 10 miles
speed in still water = s
speed of current = 4 mph
speed with current = s + 4
speed against current = s - 4
time = t
speed = distance/time
distance = speed * time
With current:
90 = (s + 4) * t
Against the current:
10 = (s - 4) * t
We have a system of equations:
90 = (s + 4) * t
10 = (s - 4) * t
90 = ts + 4t
10 = ts - 4t
Subtract the second equation from the first equation.
80 = 8t
10 = t
t = 10
10 = t(s - 4)
10 = 10(s - 4)
1 = s - 4
s = 5
Answer: The speed in still water is 5 miles per hour.
Answer: a) 
b) 
c) 
d) 
Step-by-step explanation:
Since f is an exponential function.
So, it is expressed as
Here f is the present value
p is the initial value
r is the rate of growth per time period
t is the time period.
(a) b represents the 1-unit growth factor for f.
(b) c represents the n n-unit growth factor for f.
(c) d represents the m m-unit growth factor for f.
Write a formula that expresses c in terms of b.
Since
Hence, a) b) c) d)
