You would need to draw a graph or get some graph paper and plot those points. Then calculate the rise and the run. Rise is over the run. Then that is your slope. You get the rise by counting how many units up or down it takes to get to the point, and for the run, you count how many units across it is to get to the point. don't forget, if your units are going in a negative direction, then the number will be negative.
Answer: 5(k)
Step-by-step explanation: “k”times “t” equals 6t-9 so if “k” times “t” equals 21, 6t-9=21, add 9 to 21 which equals 30 so then you divide 30 by 6 to get 5. “t”=5 which means the solution is 5(k)
(I’m just a sixth grader dont blame me if I couldn’t do this)
Answer:
i think it would be (6, -6)
Step-by-step explanation:
if the letter d is already at (2, -2) you have to multiply those numbers by 3. that gives the coordinates (6, -6)
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
