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alina1380 [7]
2 years ago
15

Can you answer this, please?

Mathematics
1 answer:
kompoz [17]2 years ago
6 0

Answer:

one of the red things

Step-by-step explanation:

if you subtract two red things from each side, you are left with two red things on one side and two E-tanks on the other. Then you can square root each side to find that one red thing equals one E-tank. Sence we don’t know the value of the red thing, this is as far as we can go

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What is the slope of the line represented by the following equation​
Lapatulllka [165]

Answer:

D 2

Step-by-step explanation:

hope this helps you

5 0
3 years ago
Figure ABCD is a parallelogram. Parallelogram A B C D is shown. Angle B is (2 n + 32) degrees and angle D is (4 n minus 2) degre
Kobotan [32]

Answer:

n=17

Step-by-step explanation:

you have to set the two equations equal to each other because its angles are the same. once you do this, its just simple algebra, trying to solve for n. Hope this helps :)

8 0
3 years ago
Read 2 more answers
How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Fantom [35]
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
4 0
3 years ago
Please help!!! I would like an explanation along with your answer. Thanks
Tpy6a [65]

Answer:

11.2 feet

Step-by-step explanation:

The two furthest corners of the bed are at (8, 6) and (5, 10).  To determine which is the furthest from the origin, use the distance formula.

d = √((x₂ − x₁)² + (y₂ − y₁)²)

d = √((8 − 0)² + (6 − 0)²)

d = 10

d = √((x₂ − x₁)² + (y₂ − y₁)²)

d = √((5 − 0)² + (10 − 0)²)

d = 5√5

d ≈ 11.2

Therefore, the corner at (5, 10) is the furthest from the origin, about 11.2 feet away.

8 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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