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Kay [80]
3 years ago
14

How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
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Answer:

third side = 4

Step-by-step explanation:

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3 years ago
What is the measure of the hypotenuse?
SVETLANKA909090 [29]

Answer:

To find the hypotenuse you need to use the Pythagorean Theorem which is

a^2+b^2=c^2

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5^2+12^2=c^2

We want to find what c equals so we are first gonna simplify

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we take 5^2=25, and 12^2=144, then we add them together 25+144=169

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3 years ago
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What is the function rule for this question?
Lemur [1.5K]
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a(n) = a(1)Rⁿ-¹
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