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ryzh [129]
2 years ago
6

Helpppppppppppppppppp pleaseeeeeeeeeeee!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
3 0

Answer:

A

Step-by-step explanation:

I did the math (:

Good luck

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I don’t understand this but:

The mean is the average of all the numbers combined

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Step-by-step explanation: .........................

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3 years ago
Can you work out G and H for me please. preferably telling me how you did it aswell
Veronika [31]
Abd is a right angled triangle so by pythagoras we know
{g}^{2}  =  {11}^{2}  +  {13}^{2}  \\  {g}^{2}  = 290 \\ g =  \sqrt{290}  \: or \: g = 17.03cm
and to calculate h we need to use the sine rule
\frac{h}{ \sin(22) }  =  \frac{g}{ \sin(32) }  \\  \frac{h}{ \sin(22) }  =  \frac{17.03}{ \sin(32) }  \\ h =  \frac{17.03}{ \sin(32) } \times  \sin(22)   \\ h = 12.04cm
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3 years ago
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((-2^2)(-1^-3))•((-2^-3)(-1^5))^-2
Vitek1552 [10]

Answer:

  256

Step-by-step explanation:

A calculator works well for this.

_____

None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.

1 to any power is still 1, so the factors (1^n) can be ignored.

After you ignore all of the things that can be ignored, your problem simplifies to ...

  (2^2)(2^-3)^-2

The rules of exponents applicable to this are ...

  (a^b)^c = a^(b·c)

  (a^b)(a^c) = a^(b+c)

Then your product simplifies to ...

  (2^2)(2^((-3)(-2)) = (2^2)(2^6)

  = 2^(2+6)

  = 2^8 = 256

3 0
3 years ago
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