Answer:
BK=9
Step-by-step explanation:
A midsegment is one half of the length of the base. So, If the base, which is ST is 18, the midsegment will be 18/2=9
Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
100/40×20.
100/40=2•5
2•5×20=50
the answer is 50
Answer:
Slide 1:
1. Solution = (-3,2)
<em>y = 2x - 1</em>
<em>y = 3/2x + 6</em>
2. No solution
<em>y = -4/2x + 4</em>
<em>y = -4/2x - 5</em>
Slide 2:
3. Solution = (1, -6) ONE SOLUTION
4. Solution = (-4, -1) ONE SOLUTION
p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4
I really hope this helped :)
