Given:
The system of equations:
To find:
The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.
Solution:
We have,
...(i)
...(ii)
The coefficient of x in (i) and (ii) are 1 and 
respectively.
To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.
It means, we have to convert into -1. It is possible if we multiply the equation (ii) by -5.
On multiplying equation (ii) by -5, we get
...(iii)
On adding (i) and (iii), we get
Here, x is eliminated.
Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.
Answer:
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Step-by-step explanation:
Volume V = length l^3
V = x^3
Differentiating both sides;
dV/dt = 3x^2 dv/dt
Given;
x = 10 in
dx/dt = 0.5 in/sec
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Answer:
No
Step-by-step explanation:
because it doesn't pass through the origin.
4J-7S
21/7=3
multiply both sides by 3
12J-21S
12 cups of juice to make 21 cups of soda
Answer: Coin A is $20, coin B is $10
Explanation:
A + B = $30
B = $10
$10 x 2 = $20
A = $20
$20 + $10 = $30
