Answer:
<em>Given : uy=0 ay=g=9.8m/s2</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 m</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=u</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=uy direction : Vy=uy+ayT</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=uy direction : Vy=uy+ayT∴ Vy=0+9.8×3=29.4m/s</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=uy direction : Vy=uy+ayT∴ Vy=0+9.8×3=29.4m/sAlso VxVy=tan45o=1</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=uy direction : Vy=uy+ayT∴ Vy=0+9.8×3=29.4m/sAlso VxVy=tan45o=1⟹ Vx=Vy=29.4 m/s</em>
<em>Given : uy=0 ay=g=9.8m/s2Let the projectile's initial velocity be u.Time of flight T=3 s (given)Using T=g2h ⟹h=2gT2∴ h=29.8×32=44.1 mx direction : ax=0 ⟹Vx=uy direction : Vy=uy+ayT∴ Vy=0+9.8×3=29.4m/sAlso VxVy=tan45o=1⟹ Vx=Vy=29.4 m/sThus initial speed of the projectile u=Vx=29.4m/</em>
<em>L</em><em>U</em><em>V</em><em>,</em>
<em>A</em><em>R</em><em>I</em><em>A</em><em>❤</em>