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OleMash [197]
3 years ago
7

A metal block suspended from a spring balance is submerged in water. You observe that the block displaces 55 cm3 of water and th

at the balance reads 4.3 N. What is the density of the block?
Physics
1 answer:
DiKsa [7]3 years ago
4 0

Answer:

8977.7 kg/m^3

Explanation:

Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3

Reading of balance when block is immersed in water = 4.3 N

According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.

Buoyant force = weight of the water displaced by the block

Buoyant force = Volume of water displaced x density of water x g

                        = 55 x 10^-6 x 1000 x .8 = 0.539 N

True weight of the body = Weight of body in water + buoyant force

m g = 4.3 + 0.539 = 4.839

m = 0.4937 kg

Density of block = mass of block / volume of block

= \frac{0.4937}{55\times10^{-6}}

Density of block = 8977.7 kg/m^3

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The highest point of the wheel is the position of the wheel when its potential energy is greatest.

<h3>At what position of the wheel potential energy is greatest?</h3>

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4 0
3 years ago
Can I improve the design of my simple machine? How?
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12345

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5 0
3 years ago
What conventions are used in SI to indicate units
klemol [59]

Answer:

<u>Conventions used in SI to indicate units are as follows:</u>

  • Only singular form of units are used. for example: use kg and not kgs.
  • Do not use full stop after the abbreviations of any unit. for example: do not use kg. or cm.
  • Use one space between last numeric digit and SI unit. for example: 10 cm, 9 km.
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3 years ago
How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the
AnnyKZ [126]

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

7 0
3 years ago
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