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4 years ago

What happens to a light wave when it travels from air glass?

Physics

1 answer:

iVinArrow [24]4 years ago

5 0

Its speed decreases, its wavelength increases, and its frequency Remains the Same.

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Which statement describes how light behaves when it strikes a translucent material?

lord [1]

I believe the answer is A. Light is scattered.

6 0

3 years ago

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A closed, rigid tank fitted with a paddle wheel contains 2 kg of air, initially at 300 K. During an interval of 5 minutes, the p

anzhelika [568]

Answer:

The final temperature of the air is $T_2= 605 K$

Explanation:

We can start by doing an energy balance for the closed system

$\Delta KE+\Delta PE+ \Delta U = Q - W$

where

$\Delta KE$ = the change in kinetic energy.

$\Delta PE$ = the change in potential energy.

$\Delta U$ = the total internal energy change in a system.

Q = the heat transferred to the system.

W = the work done by the system.

We know that there are no changes in kinetic or potential energy, so $\Delta KE = 0$ and $\Delta PE=0$

and our energy balance equation is $\Delta U = Q - W$

We also know that the paddle-wheel transfers energy to the air at a rate of 1 kW and the system receives energy by heat transfer at a rate of 0.5 kW, for 5 minutes.

We use this information to calculate the total internal energy change $\Delta U=W+Q$ using the energy balance equation.

We convert the interval of time to seconds $t = 5 \:min = 300\:s$

$\Delta \dot{U}=\dot{W}+ \dot{Q}\\=\Delta U=(W+ Q)\cdot t$

$\Delta U=(1 \:kW+0.5\:kW)\cdot 300\:s\\\Delta U=450 \:kJ$

We can use the change in specific internal energy $\Delta U = m(u_2-u_1)$ to find the final temperature of the air.

We are given that $T_1=300 \:K$ and the air can be describe by ideal gas model, so we can use the ideal gas tables for air to determine the initial specific internal energy $u_1$

$u_1=214.07\:\frac{kJ}{kg}$

Next, we will calculate the final specific internal energy $u_2$

$\Delta U = m(u_2-u_1)\\\frac{\Delta U}{m} =u_2-u_1$

$\frac{\Delta U}{m} =u_2-u_1\\u_2=u_1+\frac{\Delta U}{m}$

$u_2=214.07 \:\frac{kJ}{kg} +\frac{450 \:kJ}{2 \:kg}\\u_2= 439.07 \:\frac{kJ}{kg}$

With the value $u_2=439.07 \:\frac{kJ}{kg}$ and the ideal gas tables for air we make a regression between the values $u = 434.78 \:\frac{kJ}{kg},T=600 \:K$ and $u = 442.42 \:\frac{kJ}{kg}, T=610 \:K$ and we find that the final temperature $T_2$ is 605 K.

3 0

3 years ago

during a 3.00 s time interval,the runners position changes from x1=50.0m to x2=30.5m what was the runners average velocity

UNO [17]

Average velocity is given by the ratio of total displacement /total time taken in order to do that
thus it will be
30.5-50.0/3 = 6.5 m/s

7 0

3 years ago

What could you detect using a magnet and iron filings?

Anton [14]

Answer:

A compass can detect a magnetic field and show its direction. Iron filings can show the shape of a magnetic field. A gaussmeter can detect a field and indicate its strength.

Explanation:

4 0

3 years ago

Define pressure. write it's Si unit.<br>

tekilochka [14]

Hi :)

Pressure is the force applied perpendicular to the surface of an object per unit area

The SI unit of pressure is N/m^2

Hope this helps!

8 0

3 years ago

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