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zvonat [6]
3 years ago
14

You use software to carry out a test of significance. The program tells you that the P-value is P = 0.008. This result is

Mathematics
1 answer:
devlian [24]3 years ago
4 0
The p-value determines if the result of the test is significant or not. Very small values of p, show that the result is significant.

Based on p-value, the null hypothesis is rejected based on following criteria:

1) P-value ≤ Significance Level (α)
In this case, the null hypothesis is rejected. This shows the results do not just occur by chance and are significant.

2) P-value > Significance Level (α)
In this case, we fail to reject the null hypothesis. This shows the results are not significant.

p-value of 0.008 is very small value. Usually the α value is set to be 0.01 or 0.05, but it may vary depending on the problem we are dealing with. So such a small p-value signifies that the result is significant.
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Write The Following results into Their Equivalent logarithm form :
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In this exercise we will use the knowledge of equation of the line plus the knowledge of logarithm, like this:

3=log_8 (512)

First, we have the following values ​​informed, such as:

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Knowing that the formula for the equation of the line is given by:

y = ax \\512=8*3

The logarithm form will be:

x=log_ay\\3=log_8 (512)

See more about logarithm at brainly.com/question/7302008

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
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Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

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3 years ago
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