Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x =
x - 3 = 0; x = 3
the solutions are
Both values are real numbers, therefore correct option is b
Answer:
Alexander is incorrect because the expressions are not equivalent.
Step-by-step explanation:
If the expression is evaluated for any value of x, y; the result will not be same.
For instance, let assume x = 1 and y = 2
3x + 4y = 3 + 4 = 7
(3)(4) + xy = (3)(4) + (1 * 2) = 12 + 2 = 14
So, the expressions are not the same and Alexander is incorrect.
-2x + 16 < = 10
-2x < = 10 - 16
-2x < = - 6
x > = -6/-2
x > = 3............so any number that is 3 or above is in the solution set
Answer:
Step-by-step explanation:
Given
Required
Find x such that:
This gives:
Collect like terms
Expand
Factorize
Factor out x - 1
Solve: