Help me please it would help me

Mathematics

1 answer:

vova2212 [387]2 years ago

5 0

<h3>Answer: Choice C</h3>

======================================================

Explanation:

The x coordinate of the preimage point Q is x = 6.

The x coordinate of the image point Q' is x = 21.

The ratio of image over preimage is 21/6 = (3*7)/(3*2) = 7/2

You'll get this same value if you do the same steps with the y coordinates.

Therefore, the scale factor is 7/2 and the dilation rule is $(x,y) \to \left(\frac{7}{2}x, \frac{7}{2}y\right)$

Note: 7/2 = 3.5

You might be interested in

The half-life of a radioactive kind of tellurium is 25 minutes. If you start with 88 grams of it, how much will be left after 50

LUCKY_DIMON [66]

Notice that 50 minutes is twice the half-life.

After 25 minutes, half of the starting amount remains, so that 88g decays to 44g.

After another 25 minutes (a total of 50 minutes), the 44g will decay to 22g.

5 0

3 years ago

In your own words, explain the steps you would need to take to find slope from data in a table. Brainly work your magic.

mr_godi [17]

Answer:

In order to find the slope, you need to find the difference in the x values and the difference in the y values. To do this, you write out y2-y1/x2-x1, insert your x and y values, and get your answer. Then, you find your y-intercept (where the x value is 0).

6 0

3 years ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

hammer [34]

Answer:

a) The probability that this whole shipment will be accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

$P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007$