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2 years ago

Please help me with this math problem!! NO LINKS PLEASE!! I will give brainliest!!

Mathematics

1 answer:

zepelin [54]2 years ago

7 0

The two tangent theorem

RS = RT

So ΔRST = isosceles triangle

∠S = ∠T =( 180° - (48°) : 2 = 66°

∠TSR = 66°

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Claudia tiene 3/6 de un

KengaRu [80]

En este problema simplemente tenemos que usar la suma de fracciones.

Veremos que entre ambos tienen un frasco entero de miel.

Sabemos que Clauida tiene 3/6 de un frasco de miel, y el hermano tiene 9/18 de un frasco de miel.

En total, entre ambos, tienen:

3/6 + 9/18

Para poder realizar esta suma tenemos que tener el mismo denominador en ambas fracciones, asi que podemos simplificar.

en 9/18 si dividimos numerador y denominador por 9 obtenemos:

9/18 = 1/2

en 3/6 si dividimos numerador y denominador por 3 obtenemos:

3/6 = 1/2

Así:

3/6 + 9/18 = 1/2 + 1/2 = 1

Entre ambos tienen un frasco entero de miel.

Sí quieres aprender más, puedes leer.

brainly.com/question/19527206

3 0

3 years ago

Lily quinn makes $12.50 an hour she works four hours on monday

Reil [10]

For 1 hour, she makes = $12.50
So, for 4 hour, it would be: 12.50 * 4 = $50

In short, Your Answer would be $50

Hope this helps!

5 0

3 years ago

Read 2 more answers

X^2+y^2=1 yes or no relation represents a function or not

sleet_krkn [62]

We are asked to decide if the expression:

x^2 + y^2 = 1 represents a function.

We recall that in order to have a function, we need for a given value of x to have a SINGLE value of y associated with it.

So in this case, when x is 0 for example, we have the following:

0^2 + y^2 = 1

then y^2 = 1

and we realize that there are TWO values of y whose square form gives 1 (one is 1 and the other -1) Therefore, this relationship is NOT a function, since for example when x = 0 there are TWO values of y to which that x is associated (y = 1 and y = -1).

So please select that this is NOT a function for your answer.

6 0

1 year ago

Jan wants to protect the wooden box in question 4a by painting varnish on all of the outside surfaces, including the bottom. Wil

Dafna1 [17]

Answer:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

Explanation is given below

Step-by-step explanation:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

In order to answer this question we need to have the dimensions of the box.

Let's suppose there are 6 outside surfaces of the box and are equal in dimension including the bottom side which Jan wants to varnish.

So,

Let's suppose,

Surface area of the cube = 6 $a^{2}$

Here, Surface area = 275 square inch

Surface area of the cube = 6 $a^{2}$ = 275 square inch

$a^{2}$ = 275/6 = 45.833

a = $\sqrt{45.833}$

a = 6.77 inches

Now, for the amount of the varnish, we need the spreading rate of the varnish to be used on the box,

Let's suppose it is = 11 square incher per litre.

So,

Required Varnish = Surface area / Spreading rate

Required varnish = 275 / 11

Required varnish = 25 liters

If the 1 container of varnish contains 25 liters then it will be sufficient to protest the outside surfaces of the box.

6 0

3 years ago

A briefcase has a three- digit lock code that doesn't include zero as a digit. What is the probability that the lock code consis

storchak [24]

Answer:

1/21.

Step-by-step explanation:

There are 9 digits and the total number of permutations of 3 from 9 is 9P3

= 9!/6! = 504.

There are 4 even digits so the number of permutations of 3 from these 4 is 4! (4-3)! = 4*3*2 = 24.

So the required probability = 24/504

= 1/21.

5 0

3 years ago