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sergeinik [125]
3 years ago
7

Find the least common denominator for these two rational expressions s^3/s^2-2s+1 -2/s^2-4s+3

Mathematics
2 answers:
lidiya [134]3 years ago
7 0

Answer:

s⁴-6s³+12s²-10s+3


Step-by-step explanation:

s³/(s²-2s+1) - 2/(s²-4s+3)

The denominators are (s²-2s+1) and (s²-4s+3). Since one is not a multiple of the other, the least common denominator will be their product.

(s²-2s+1)(s²-4s+3) = s⁴-4s³+3s²-2s³+8s²-6s+s²-4s+3

                             = s₄ +(-4s³-2s³)+(+3s²+8s²+s²)+(-6s-4s)+3

                              = s⁴-6s³+12s²-10s+3

Anuta_ua [19.1K]3 years ago
4 0

Answer: \bold{\dfrac{s^4-3s^3-2s+2}{(s-1)(s-1)(s-3)}}

<u>Step-by-step explanation:</u>

Factor both denominators to see which factors are missing from each denominator. Then multiply both fractions so they have the same LCD.

  \dfrac{s^3}{s^2-2s+1}+\dfrac{-2}{s^2-4s+3}

=\dfrac{s^3}{(s-1)(s-1)}+\dfrac{-2}{(s-1(s-3)}

=\dfrac{s^3}{(s-1)(s-1)}\bigg(\dfrac{s-3}{s-3}\bigg)+\dfrac{-2}{(s-1(s-3)}\bigg(\dfrac{s-1}{s-1}\bigg)

=\dfrac{s^4-3s^3-2s+2}{(s-1)(s-1)(s-3)}


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