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Lemur [1.5K]
3 years ago
10

8/7 x 7/8 solve this.

Mathematics
2 answers:
Helen [10]3 years ago
8 0

Answer: 1

Step-by-step explanation: Because it is

LuckyWell [14K]3 years ago
4 0

Answer: 1

Step by step: i think

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How do you group quadratics?
barxatty [35]
If you have a quadratic equation in the form ax^2+bx+c
Step 1) Determine the product of AC (the coefficients in a quadratic equation)
Step 2) Determine what factors of a⋅ca⋅c sum to bb
Step 3) "ungroup" the middle term to become the sum of the factors found in step 2
Step 4) group the pairs.
3 0
3 years ago
PLEASE HELP OUT!!! im super lost.
Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 -  (-3)

f(-3) = 5 +3

f(-3) = 8

3 0
2 years ago
Please I need help with this and show your steps
Lorico [155]

Answer:

-30/15 or -2

Step-by-step explanation:

2+8 = 10

3+2 = 5

14-2 = 12

4-1 = 3

10/5 - 12/3

(Find GCF)(GCF = 15)(5 times 3)

30/15 (10/5 times 3)

60/15 (12/3 times 5)

30/15 - 60/15 = -30/15 --> -2(simplified to 2)

7 0
2 years ago
Read 2 more answers
A car's position is given by s(t) = {3 – 5t? + 7t hundreds of meters with t in minutes.
Nadya [2.5K]

Answer:

A) (1 s, 2.3 s)

B) (-4 m/s², 3.8 m/s²)

Step-by-step explanation:

The car's position which is the distance is given by the equation;

s(t) = t³ - 5t² + 7t

A) Velocity is the first derivative of the distance. Thus;

v(t) = ds/dt = 3t² - 10t + 7

At v = 0, we have;

3t² - 10t + 7 = 0

Using quadratic formula, we have;

t = 1 and t = 2.3

Thus, time at velocity of 0 is t = (1 s, 2.3 s)

B) acceleration is the derivative of the velocity. Thus;

a(t) = dV/dt = 6t - 10

At velocity of 0, we got t = 1 and t = 2.3

Thus;

a(1) = 6(1) - 10 = -4 m/s²

a(2.3) = 6(2.3) - 10 = 3.8 m/s

Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)

8 0
3 years ago
What can be said about the relationships between triangles and circles? Check all that apply.
ycow [4]

Answer:

The answers are:

A. Exactly one circle can be inscribed in a given triangle.

C. Many triangular shapes can be circumscribed about a given circle.

Step-by-step explanation:

I just took the quiz as well. Good luck!

3 0
3 years ago
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