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brilliants [131]
2 years ago
6

Solve for z. 2 39z+ 17z = 0

Mathematics
1 answer:
Tamiku [17]2 years ago
8 0

Answer:

Z = 0

Step-by-step explanation:

Z is 0 because there’s no other possible solutions

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H
Keith_Richards [23]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?
Gnoma [55]

There would be 12 people at the party!

In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n.

Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66.

This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party.

Since 66 is a relatively small number, you can also solve this problem with a hand calculator. Add 1 + 2 = + 3 = +... etc. until the total is 66. The last number that you entered (11) is n.

Hope this helps!

3 0
2 years ago
Read 2 more answers
What is the value of x in the equation 3x - 4y=65, when y=4?<br> N
4vir4ik [10]

Answer:

x =27

Step-by-step explanation:

3x - 4y=65

lets substitute the value of y in the equation:

3x -4(4) =65

3x = 65 +16

3x= 81

x= 81/3

x = 27

3 0
3 years ago
In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q
siniylev [52]

Answer:

∠Q  = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

Hence using the notation

SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering  ∠Q and the given sides

PR=16cm is the opposite side,

PQ= 12 cm is the adjacent side hence we use TOA

Tan Q = 16/12 =

Q = Arc tan 16/12

= 53.13 degrees

5 0
2 years ago
I need help with these two questions!! I got 72° for Question 7, I don't know I need help with both of them!! PLEASE HELP!! :)
Nat2105 [25]

Answer:

7. 49

8. 10.4

Step-by-step explanation:

7) our hypotenuse is 8, and the side opposite the base of ladder and ground angle is 6, therefore we can use Sin

sin = opposite/hypotenuse

sin(x) = 6/8 = 3/4

sin-1(3/4) = 49

8) using the theorem that alternate exterior angles are congruent

the angle opposite side x is 30

tan = opposite/adjacent

tan(30) = x/18

x = 18tan(30) = 6√(3) = 10.4

you can also use 30-60-90 special right triangles.

the side opposite 30 is x

side opposite 60 is x√(3)

and side opposite 90 is 2x

3 0
3 years ago
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