Assuming diallelic genes that express complete d0minance, <em>4/16 = 25% </em><em>of the </em><em>progeny</em><em> is expected to be </em><em>male</em><em> with barred feathers and a pea comb.</em>
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Available data</u></h3>
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- Male chickens carry two Z chromosomes.
- Female chickens carry one Z and one W chromosomes.
- The gene for barring is in the Z chromosome.
- The barred trait is d0minant over unbarred trait.
- Gene for comb is aut0s0mic.
- The rose comb is d0minant over the pea comb.
Assuming diallelic genes that express complete d0minance, let us say that
Cross: unbarred male heter0zyg0us for the rose-comb with a barred female with a single comb.
Parentals) Z⁻Z⁻ Rr x Z⁺W rr
Gametes) Z⁻ R, Z⁻ R, Z⁻ r, Z⁻ r
Z⁺r, Z⁺r, Wr, Wr
Punnett square) Z⁻ R Z⁻ R Z⁻ r Z⁻ r
Z⁺r Z⁺Z⁻Rr Z⁺Z⁻Rr Z⁺Z⁻rr Z⁺Z⁻rr
Z⁺r Z⁺Z⁻Rr Z⁺Z⁻Rr Z⁺Z⁻rr Z⁺Z⁻rr
Wr WZ⁻Rr WZ⁻Rr WZ⁻rr WZ⁻rr
Wr WZ⁻Rr WZ⁻Rr WZ⁻rr WZ⁻rr
F1) 4/16 individuals are expected to be males with barred feathers and rose combs, Z⁺Z⁻Rr.
4/16 individuals are expected to be males with barred feathers and pea combs, Z⁺Z⁻rr.
4/16 individuals are expected to be females with unbarred feathers and rose combs, WZ⁻Rr.
4/16 individuals are expected to be females with unbarred feathers and pea combs, WZ⁻rr.
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<em>4/16 = 25% </em><em>of the </em><em>progeny</em><em> is expected to be </em><em>male</em><em> with barred feathers and a pea comb.</em>
You can learn more about crosses with two genes at
brainly.com/question/4441612