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3 years ago

Select the correct answer. Which equation could possibly represent the graphed function?

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

I Don’t Know If Still Need The Answer But It Should Be A.

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Priya found x=3 and x=-1 as solutions to 3x^2-6x-9=0. Is she correct sow how you know

olga55 [171]

Answer:

Step-by-step explanation:

6 0

3 years ago

Plz help me brainliest will be reward if right and 25 points

slega [8]

Answer:

the answer is f(x) = 6x + 1/6

Step-by-step explanation:

the g(x) ones y intercept is : 0,-6

the -6k(x) ones y intercept is : 0 , -6

the f ( x) ones y inetrcept is ; 0 , 1/6

the h (x) ones y intercept is : 0 , 6

5 0

3 years ago

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Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

8 0

2 years ago

A tank holds 50 gal of water, which drains from a leak at the bottom, causing the tank to empty in 20 min. The tank drains faste

kirza4 [7]

Answer:

(a) V(0) = 50 gal, V(20) = 0 gal

(b)At t= 0 the tank is full.

At t=0 the tank is empty

(c)

Time volume

0 50 gal

5 37.5 gal

10 25 gal

15 12.5 gal

20 0 gal

(d)

Net change of volume = 50 gal

Step-by-step explanation:

Given that the capacity of the tank is 50 gal.

Torricelli's Law gives the volume of water remaining in the tank after t minutes as

$V(t)=50(1-\frac{t}{20})^2$

(a)

To find V(0), we put t = 0 in the above equation

$V(0)=50(1-\frac{0}{20})^2$

$=50(1-0)^2$

= 50 gal

To find V(20), we put t =2 0 in the above equation

$V(20)=50(1-\frac{20}{20})^2$

$=50(1-1)^2$

= 0 gal

(b)

At t= 0 the tank is full.

At t=0 the tank is empty.

(c)

Time V(t)

0 $50(1-\frac{0}{20})^2=50 \ gal$

5 $50(1-\frac{5}{20})^2=37.5 \ gal$

10 $50(1-\frac{10}{20})^2=25 \ gal$

15 $50(1-\frac{15}{20})^2=12.5 \ gal$

20 $50(1-\frac{20}{20})^2=0$

(d)

Net change of volume = V(0) -V(20)

=(50-0) gal

= 50 gal

3 0

3 years ago

3x - 7 = 17 is it <br><br> (x = -8) or (x = 8 )

Schach [20]

Answer:

The answer is x = 8

5 0

4 years ago

Read 2 more answers