Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
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The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
Smaller because off the number value and places.
To add these amounts together, we must first find their least common multiple in order to get common denominators (b/c when you add fractions, the denominators must be the same).
We'll start by listing some of their multiples.
To do this, count by whatever the denominator is:
4 1/2 (denominator is 2): 2 4 6 8 10 12 14
2 1/4 (denominator is 4): 4 8 12 16
6 1/3 (denominator is 3): 3 6 9 12 15
Look and see which is the first multiple that all three denominators have. Circle them if it helps you. In this case, it's 12.
So now we have to multiply the denominators by whatever number it takes to reach 12, and multiply by the same number to the numerator:
4 1/2 (times 6 to both top and bottom) =
4 6/12
2 1/4 (times 3) = 2 3/12
6 1/3 (times 4) = 6 4/12
Add all these fractions together, and you get 12 13/12, which is equal to 13 1/12.
Thus, Peter makes a total of 13 1/2 cups.
Hope this made sense! tell me if anything is confusing/incorrect :))
The right answer is Option C : 5
Step-by-step explanation:
Let,
The numerator of fraction = x
The denominator of a fraction is 10 more than its numerator.
When 1/3 is added to this fraction,
the resulting fraction’s denominator is three times the denominator of the original fraction its numerator is 15 less than its denominator
Therefore, it becomes
Taking LCM on left side
Multiplying both sides by 3(x+10)
The numerator of original fraction is 5.
The right answer is Option C : 5
Keywords: fraction, addition
Learn more about fractions at:
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