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Umnica [9.8K]
3 years ago
10

The volume of a right circular cylinder is 1100 cm3 and the radius of its base is 5 cm. Calculate its curved surface area.

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

(A) 440 cm²

Step-by-step explanation:

Volume of a right circular cylinder  =  1100 cm²

πr2 h =  1100 cm³

Here r = 5

(22/7) ⋅ (5)2 ⋅ h  =  1100

h  = 2/7

Curved surface area of cylinder  =  2 πr h

 =  2 ⋅ (22/7) ⋅ 5 ⋅ (2/7)

=  440 cm²

So, the curved surface area of cylinder is  440 cm²

Scorpion4ik [409]3 years ago
3 0

Answer:

  • (C) 440 cm²

Step-by-step explanation:

<u>Volume:</u>

  • V = πr²h

<u>Given r = 5 cm and V = 110 cm³, find h:</u>

  • 1100 = π(5²)h
  • 1100/25 = πh
  • 44 = πh

<u>Curved surface area:</u>

  • S = 2πrh = 2*5*πh = 10*44 = 440 cm²

Correct choice is C

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P(x)=(x-2)(x-4)(x-5)
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The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

So, we have:

<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

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<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

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<u>P(x) =-5(x-2)(x-4)(x+5)</u>

Constant = -5 \times -2 \times -4 \times 5

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Hence, the constant is -200

Read more about polynomials at:

brainly.com/question/2833285

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