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Umnica [9.8K]
3 years ago
10

The volume of a right circular cylinder is 1100 cm3 and the radius of its base is 5 cm. Calculate its curved surface area.

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

(A) 440 cm²

Step-by-step explanation:

Volume of a right circular cylinder  =  1100 cm²

πr2 h =  1100 cm³

Here r = 5

(22/7) ⋅ (5)2 ⋅ h  =  1100

h  = 2/7

Curved surface area of cylinder  =  2 πr h

 =  2 ⋅ (22/7) ⋅ 5 ⋅ (2/7)

=  440 cm²

So, the curved surface area of cylinder is  440 cm²

Scorpion4ik [409]3 years ago
3 0

Answer:

  • (C) 440 cm²

Step-by-step explanation:

<u>Volume:</u>

  • V = πr²h

<u>Given r = 5 cm and V = 110 cm³, find h:</u>

  • 1100 = π(5²)h
  • 1100/25 = πh
  • 44 = πh

<u>Curved surface area:</u>

  • S = 2πrh = 2*5*πh = 10*44 = 440 cm²

Correct choice is C

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3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
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For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

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Then

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P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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