The volume of a right circular cylinder is 1100 cm3 and the radius of its base is 5 cm. Calculate its curved surface area.

Mathematics

2 answers:

iogann1982 [59]2 years ago

5 0

Answer:

(A) 440 cm²

Step-by-step explanation:

Volume of a right circular cylinder = 1100 cm²

πr2 h = 1100 cm³

Here r = 5

(22/7) ⋅ (5)2 ⋅ h = 1100

h = 2/7

Curved surface area of cylinder = 2 πr h

= 2 ⋅ (22/7) ⋅ 5 ⋅ (2/7)

= 440 cm²

So, the curved surface area of cylinder is 440 cm²

Scorpion4ik [409]2 years ago

3 0

Answer:

Step-by-step explanation:

Volume:

V = πr²h

Given r = 5 cm and V = 110 cm³, find h:

1100 = π(5²)h
1100/25 = πh
44 = πh

Curved surface area:

S = 2πrh = 2*5*πh = 10*44 = 440 cm²

Correct choice is C

You might be interested in

determine the quadratic function of f whose graph is given. The vertex is (1,-3) and the y-intercept is -2

LuckyWell [14K]

Hmmm the y-intercept is at -2? what does that mean? well, is where the graph "intercepts" or touches the y-axis, and when that happens, x = 0, so the point is really ( 0 , -2 ).

and we know where the vertex is at. Let's assume a vertical parabola, in which case the squared variable is the "x".

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=1\\
k=-3
\end{cases}\implies y=a(x-1)^2-3
\\\\\\
\textit{now, we also know that }
\begin{cases}
x=0\\
y=-2
\end{cases}\implies -2=a(0-1)^2-3
\\\\\\
1=a(-1)^2\implies \boxed{1=a}\qquad thus\implies 
\begin{cases}
y=1(x-1)^2-3\\
\textit{or just}\\
y=(x-1)^2-3
\end{cases}$

6 0

3 years ago

A phone company charges a base fee of $12 per month plus an additional charge per minute. The monthly phone cost C can be repres

Rina8888 [55]

Answer:

It’s actually m = (C - 12) /3 But I don’t see it in the 4 option you have.

Step-by-step explanation:

C = 12+ am

C - 12 = am

(C - 12) /a = m

3 0

3 years ago