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2 years ago

What are the domain and range of the function?

Mathematics

1 answer:

kolbaska11 [484]2 years ago

8 0

Answer:

$x$ = - 2/7

Alternate form: - 0.285714

Step-by-step explanation:

1- Substitute f ( x ) = 0

Reorder

f ( $x$ ) = $x$ x 2 - 16 $x$ - 4

2- Collect like terms

0 = 2 $x$ - 16 $x$ - 4

3- Move the variable to the left

0 = - 14 $x$ - 4

4- Divide both sides

14 $x$ = - 4

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If p is inversely proportional to the square of q, and p is 16 when q is 11, determine p

Blizzard [7]

Answer:

p = 121

Step-by-step explanation:

inveresly proportional

pq² = k

find k the constant of proportionality

p is 16 when q is 11,

16 * 11² = k

k = 1,936

----------------------------

pq² = 1,936

determine p when q is equal to 4.

p * 4² = 1,936

16p = 1,936

p = 1,936/16

p = 121

5 0

2 years ago

Read 2 more answers

What is the solution to the system of equations shown on the graph?

Dmitry_Shevchenko [17]

The solution is (-1,-3), it is where the two lines meet.

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2 years ago

I NEED HELP ASAP Write a mathematical sentence for the inequality: Three times the sum of a number and two is greater than zero.

Pepsi [2]

Answer:

3x+2>0

Step-by-step explanation:

the 3x is there because its 3 times an unknown # and add 2, its also > sign because its greater than 0

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2 years ago

Use the given information to find the p-value. also use a0.05 significance level and state the conclusion about the null hypothe

omeli [17]

Answer:

(a) C: 0.0465 ; reject the null hypothesis

(b) B: 0.3409 ; fail to reject the null hypothesis

Step-by-step explanation:

Firstly, the decision rule based on P-value to reject the null hypothesis or fail to reject the null hypothesis is given by;

If the P-value of test statistics is less than the level of significance, then we have sufficient evidence to reject our null hypothesis.

If the P-value of test statistics is more than the level of significance, then we have insufficient evidence to reject our null hypothesis due to which we fail to reject our null hypothesis.

(a) Now, we are given alternate hypothesis, $H_1$ : p < 3/5

Also, z test statistics is -1.68. Since this is a left tailed test, so P-value is given by;

P-value = P(Z < -1.68) = 1 - P(Z $\leq$ 1.68)

= 1 - 0.95352 = 0.0465

Since, the P-value of test statistics is less than the level of significance as 0.0465 < 0.05, so we have sufficient evidence to reject our null hypothesis due to which we reject the null hypothesis.

(b) Now, we are given alternate hypothesis, $H_1$ : p > 0.383

Also, z test statistics is 0.41. Since this is a right tailed test, so P-value is given by;

P-value = P(Z > 0.41) = 1 - P(Z $\leq$ 0.41)

= 1 - 0.6591 = 0.3409

Since, the P-value of test statistics is more than the level of significance as 0.3409 > 0.05, so we have insufficient evidence to reject our null hypothesis due to which we fail to reject the null hypothesis.

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2 years ago

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3 years ago