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Lesechka [4]
3 years ago
5

Differentiate y=(6x)/(1-cot(x))

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0
\bf y=\cfrac{6x}{1-cot(x)}\implies \cfrac{dy}{dx}=\stackrel{quot ient~ru le}{\cfrac{6[1-cot(x)]~-~6x[-csc^2(x)]}{[1-cot(x)]^2}}
\\\\\\
\cfrac{dy}{dx}=\cfrac{6-6cot(x)~+~6xcsc^2(x)}{[1-cot(x)]^2}
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Which statement correctly explains how Mari could find the solution to the following system of linear equations using
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Multiply the first equation by 7 and the second equation by 2, and then add.

Step-by-step explanation:

2f - 5g=-9

-7f + 3g=4

To eliminate any variable , we need to make the coefficients same with different sign and add it

the coefficient of 'f' in first equation is 2

the coefficient of 'f' in second equation is -7

We already have different sign so we make the coefficients same

To make the coefficient same , we multiply the first equation by 7  and second equation by 2

So equation becomes

14f - 35g = -63

-14f + 6g = 8

Now when we add both equations, 'f' gets cancelled

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3 years ago
Which fraction is<br> equivalent to -3/2?
mr Goodwill [35]
The correct answer is 3/-2
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3 years ago
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kenny6666 [7]

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4 0
3 years ago
PLEEZZ
jonny [76]

4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0
3 years ago
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