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agasfer [191]
3 years ago
15

Figure B is a scaled copy of Figure A What is the scale factor from Figure A to Figureb

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

Below.

Step-by-step explanation:

About x3 bigger then figure b.

Arturiano [62]3 years ago
7 0
<h3>Explanation:</h3>
  • We already know that Figure A is the pre-image and Figure B is the image. Since the image is smaller than the pre-image, the scale factor will be less than 1.
  • We also know that the pre-image is three times greater than the image. Since the scale factor is less than 1, 3 will go in the denominator.

The scale factor from Figure A to Figure B is 1/3.

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There are 5 players on a basketball team. In a game, 4 players scored 6 scored 6 points each. The team scored a total of 34 poin
OLga [1]

Answer:

10 points

Step-by-step explanation:

you do 6 times 4 which is 24 then you do 34 - 24 which is 10 so the rest of the team scored 10 points

8 0
4 years ago
(-3,4) m= -3 how would you solve this problem
nignag [31]

you would do PEMDAS

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5 0
3 years ago
P(a) = 2a -3; find p(a) = 15
Andrei [34K]
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8 0
3 years ago
What is the solution set of the quadratic equation 8x2 +2x +1 =0?
Sidana [21]
   
\displaystyle\\&#10; 8x^2 +2x +1 =0\\\\&#10;x_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-2\pm \sqrt{2^2-4\cdot 8 \cdot 1}}{2\cdot 8}=\\\\&#10;=\frac{-2\pm \sqrt{4-32}}{16}=\frac{-2\pm \sqrt{-28}}{16}=\frac{-2\pm \sqrt{4\cdot 7\cdot(-1)}}{16}=\\\\&#10;=\frac{-2\pm 2i\sqrt{7}}{16}=\frac{-1\pm i\sqrt{7}}{8}= -\frac{1}{8}\pm  \frac{\sqrt{7}}{8}i\\\\&#10;x_1 =   \boxed{-\frac{1}{8}+  \frac{\sqrt{7}}{8}i}\\\\&#10;x_2 =   \boxed{-\frac{1}{8}-  \frac{\sqrt{7}}{8}i}\\\\&#10;x_1,~x_2~\in \mathbb{C}



4 0
3 years ago
A publishing company claims that in fall 2019, the average price of college textbooks for a single semester is $385. Suppose you
hram777 [196]

Answer:

We accept H₀ . We don´t have enough evidence to express the publisher claim is not true

Step by Step explanation:

We must evaluate if the mean of the price of college textbooks is different from the value claimed by the publisher

n < 30 then we must use t - distrbution

degree of freedom   n  - 1     df = 22 - 1     df = 21

As the question mentions " different " that means,  a two-tail test

At 0,01 significance level     α  = 0,01       α/2  =  0,005

and t(c)  = 2,831

Test Hypothesis

Null Hypothesis                      H₀          μ  =  μ₀

Alternative hypothesis           Hₐ          μ  ≠  μ₀

To calculate t(s)

t(s)  =  (  μ  -  μ₀ ) /σ/√n

t(s)  =  (  433,50 - 385 ) / 86,92 / √22

t(s)  =  2,6171

Comparing   t(c)   and t(s)

t(s) < t(c)

Then  t(s) is in the acceptance region we accept H₀. We don´t have enough evidence to claim that mean price differs from publisher claim

6 0
3 years ago
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