For this case we have that by definition, the area of a circular sector is given by:
![A = \frac {\alpha}{360}\pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%20%7B%5Calpha%7D%7B360%7D%5Cpi%20r%5E2)
Where,
- <em>r: radius of the circle
</em>
- <em>α: Central angle
</em>
Therefore, replacing values we have:
![A = \frac {30} {360} \pi (6) ^ 2\\A = 9.42 ft ^ 2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%20%7B30%7D%20%7B360%7D%20%5Cpi%20%286%29%20%5E%202%5C%5CA%20%3D%209.42%20ft%20%5E%202)
Answer:
The area of a sector bounded by a 30 ° arc is:
![A = 9.42 ft ^ 2](https://tex.z-dn.net/?f=A%20%3D%209.42%20ft%20%5E%202)
Answer:
Thank you. Here is some free info!
Step-by-step explanation:
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6t-(1/6)=9
6t=9+(1/6)
6t=9.167
t=9.167/(6)
t=1.53
I think it might be 5/7 but i’m not 100% certain
Integers are numbers and absolute value is the magnitude of the numbe non dependent of its sign (absolute value is the number as a positive) ex; the absolute value of -3 is 3... and if the original number is positive it stays the same so ex; the abosolute value of 8 is 8