Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
so
(this is wrong because 
)
The answer would be C: 2/3
There are 4 out of 6 letters that aren’t vowels (BMPC)
And 4/6 = 2/3
Answer:
Denote that line: y = ax + b
Line passes (-2, 7) and (2,-5):
=> -2a + b =7
=> 2a + b = -5
Add both side of above equations:
=> 2b = 2
=> b = 1
=> a = (-5 - 1)/2 = -3
=> Slope a = -3
Hope this helps!
:)
The legs are 5 inches long.
Use the Pythagorean theorem:
The length of the hypotenuse of the triangle is approximately 7 inches long.
