Question

Please help asap!!!!​

Answer 1

Answer:

-12

Step-by-step explanation:

Apply the radical rule :  $\sqrt[n]{-a} =-\sqrt[n]{a}$

Therefore, $\sqrt[3]{-1728} =-\sqrt[3]{1728}$

Factorise 1728:   $1728=12^3$

Therefore, $\sqrt[3]{-1728} =-\sqrt[3]{12^3}$

Apply the radical rule:  $\sqrt[n]{a^n} =a, \ \ \ \ a\geq 0$

Therefore, $-\sqrt[3]{12^3}=-12$