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Montano1993 [528]
3 years ago
6

6x+5y=15 -7x-5y=-10These are the same x and y stuff

Mathematics
1 answer:
Elodia [21]3 years ago
5 0
Answer: x=-5, y=9

You can use elimination to solve this system. By adding the two equations together, you get:
-x=5
Then solve for x by dividing both sides by -1:
x=-5

Now that you have x, substitute that into one of the equations to solve for y.
6(-5)+5y=15
-30+5y=15
5y=45
And now divide both sides by 5 to solve for y:
y=9
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On 1 st March, 2020 Mr. Mohit started a Furniture business in GANDHI NAGAR Mr. Mohit invested Rs 50,00,000.
d1i1m1o1n [39]

Answer:

Answer to the following question is as follows;

Step-by-step explanation:

Given:

Amount invested by Mr. Mohit = Rs. 50,00,000

Computation:

Books of (...... LTD)

Journal entries

Date                         Particular                        Debit        Credit

March 1         Cash                     A/C Dr.     50,00,000

                     To Capital            A/C Cr.                         50,00,000

(Being Amount invested in new business)

8 0
3 years ago
In triangle abc angle a = 40◦, side b = 11 and side c = 5. use the cosine rule to find the length of side a, to two decimal plac
Sonbull [250]
A^2 = b^2 + c^2 - 2bc cos a

    = 11^2 + 5^2 - 2*5*11 cos 40

   =  7.86 to 2 DP's

to find the remaining angles use the sine rule:-
a / sin A = b / sin B so

7.857/ sin 40 =  11 / sin B
sin B = 11 sin40 / 7.857 = 0.8999

<B = 64 degrees 

so <C = 180 - 64-40  =  76 degrees
5 0
3 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
Read 2 more answers
Compute the norm of v when v = (-8,7,4)​
dexar [7]

Answer:

the norm of V = =11.357816691601..

Step-by-step explanation:

\left\vert \overrightarrow{V} \right\vert  =\sqrt{\left( -8\right)^{2}  +\left( 7\right)^{2}  +\left( 4\right)^{2}  }

      =\sqrt{64+49+16}

      =\sqrt{129}

      =11.357816691601...

4 0
2 years ago
Assume that the following events are independent:
NNADVOKAT [17]

Answer:

D 0.61

Step-by-step explanation:


0.42

0.69

= 0.6089

7 0
4 years ago
Read 2 more answers
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