Answer:
7/9
Step-by-step explanation:
The data set represents the total number of tuba players in each of 11 different school bands. 0, 1, 3, 3, 4, 4, 4, 5, 6, 6, 8 W
DaniilM [7]
Data set: <span>0, 1, 3, 3, 4, 4, 4, 5, 6, 6, 8
minimum : 0
1st quartile: 2
median: 4
3rd quartile: 6
maximum: 8
mean: 4
mean average deviation: 1.64
interquartile range: 4
range: 8</span>
It is A. x = 2√3, y = 4√3
AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
Answer:
The probability tree is;
0.95 
0.1 0.05
[ P ]
0.9 0.15
0.85
Step-by-step explanation:
Given the data in the question;
10% of the rugby team members use steroids
so Probability of using steroid; P( use steroid ) = 10% = 0.10
Probability of not using steroid; P( no steroid use ) = 1 - 0.10 = 0.90
Since the test show positive for an athlete who uses steroids, 95% of the time.
Probability of using steroids and testing positive = 95% = 0.95
Probability of using steroids and testing Negative = 1 - 0.95 = 0.05
Also from the test, 15% of all steroid-free individuals also test positive.
so
Probability of not using steroids and testing positive = 15% = 0.15
Probability of not using steroids and testing negative = 1 - 0.15 = 0.85
To set up the probability tree, Let;
represent steroid use
represent no steroid use
represent test positive
represent test negative
so we have;
0.95 
0.1 0.05
[ P ]
0.9 0.15
0.85