Boasted is talk with excessive pride and self satisfaction about one’s achievements
The least weight of a bag in the top 5 percent of the distribution is; 246
From the complete question below, we are given;
Population mean; μ = 240
Population standard deviation; σ = 3
Z-score formula is;
z = (x' - μ)/σ
- Now, we want to find the least weight in the top 5 of the distribution and as such we will use;
1 - 0.05/2 = 0.025 as significance level
Z-score at significance level of 0.025 is 1.96
Thus;
1.96 = (x' - 240)/3
3 × 1.96 = x' - 240
x' = 240 + 5.88
x' = 245.88
Approximating to a whole number gives;
x' = 246
Complete question is;
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal, with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?
Read more about z-score at; brainly.com/question/25638875
Based on the vertices and the pre-order traversal order the tree would be visited is e, i, b, h, f, a, c, d, g.
<h3>What order will the tree be visited?</h3>
When using the pre-order traversal, the order would be from the root child node to the left child node to right child node.
The root node is the highest node which is e. From here you'll then proceed to the left roots first which means you'll go to i and then b.
From there you go to h and then f. The next nodes would be a and c.
Continuing from left to right, you'll then go to d and then g.
You'll therefore start from "e" and move to "i" and then "b" to "h" and then "f" and "a" to "c" and then to "" and finally to "g"
Find out more on the pre-order traversal at brainly.com/question/14559964.
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