Just dew it corporation reports the following balance sheet information for 2020 and 2021.

Learning about civics gives you a foundation for forming educated opinions about __________.

lubasha [3.4K]

B, your country and how to improve!

3 0

4 years ago

Songs like "fortunate son" by creedence clearwater revival, "give peace a chance" by john lennon, and "i-feel-like-i'm-fixin'-to

Viefleur [7K]

Answer:

peace

Explanation:

this songs purpose was to preach peace and convince people about how the vietnam war was bad and the country should make peace

4 0

2 years ago

A study suggests that about 80\%80%80, percent of undergraduate students are working at a job. Researchers plan to do a follow-u

Leni [432]

Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem:

The estimate of the proportion is of $\pi = 0.8$ .

The desired margin of error is of M = 0.01.

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Then, we solve for n to find the minimum sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}$

$\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2$

$n = 4329.6$

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

7 0

2 years ago

There are 16 gifts under the Christmas tree. If one- fourth of them are for Chole, how many gifts will Chole receive?

kirza4 [7]

Chole will recieve 4 gifts. This is because if we divide 16 by 4, we get 4.

4 0

3 years ago

Phase 1 TRANSCEND CLL 004 study of lisocabtagene maraleucel in patients with relapsed/refractory CLL or SLL

PIT_PIT [208]

TRANSCEND CLL 004 is a clinical trial that assesses a type of CAR T-cell therapy in patients suffering relapsed/refractory chronic lymphocytic leukemia/small lymphocytic lymphoma.

<h3>What is CAR T-cell therapy?</h3>

The chimeric antigen receptor (CAR) T-cell therapy is a gene therapy based on genetic engineering to produce T cells that are able to target specific antigens.

The chimeric antigen receptor (CAR) T-cell therapy may result very useful to kill specific cancer cells.

In conclusion, TRANSCEND CLL 004 is a clinical trial that assesses a type of CAR T-cell therapy in patients suffering relapsed/refractory chronic lymphocytic leukemia/small lymphocytic lymphoma.

Learn more about gene therapy here:

brainly.com/question/315648

#SPJ1

8 0

2 years ago