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Taya2010 [7]
2 years ago
10

Which deal on large bags of candy is best deal? Which is the worst deal? How do you know? Can you find more than one way to dete

rmine this? (Please help)
Product/ Cost Pieces / Cost per Piece

Runts, Gobstoppers, Baby Ruth ->
cost - $6.99
cost per price - 90

Almond Joy, Whoppers, Kit Kats
Cost - $15.99
Cost per price - 160

Starburst, Skittles, Snickers
cost - $15.99
Cost per price - 150

Life Savers Yummies, Skittles
cost - $13.69
Cost per price - 95

M&M's, Twix and more
Cost - $14.74
Cost per price - 135

Snickers
Cost - $9.94
Cost per price - 45
Mathematics
1 answer:
8090 [49]2 years ago
6 0

Answer:

Life savers yummies, skittles mark i think

Step-by-step explanation:

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Are the two graphs functions or not and why or why not
Anna [14]

Answer:

Hi there!

The first one is not a function because it crosses twice using the vertical line test while the second one is a function.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Triangles DEF and D'E'F' are shown on the coordinate plane below:
Lorico [155]

The <em><u>correct answer</u></em> is:

90° clockwise

Explanation:

Comparing the image points to the pre-image points, we can see that in every ordered pair, x and y have been switched and x has been negated.  Algebraically, this means (x, y)→(y, -x).

This is the same mapping that a 90° clockwise rotation performs, so that is our answer.

5 0
3 years ago
Read 2 more answers
What is the volume of the composite figure?
ehidna [41]

\huge\boxed{\text{C.}\ 372\ \text{cubic inches}}

We will find the volume of each rectangular prism separately.

<h3>Top Figure</h3>

12*4*4

12*16

\boxed{192}

<h3>Bottom Figure</h3>

12*5*3

12*15

\boxed{180}

<h3>Adding Together</h3>

192+180

\large\boxed{372\ \text{in}^{3}}

7 0
3 years ago
Part I
klemol [59]
It depends on the shape it may be rotation
6 0
3 years ago
How do you do question b?
notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\

-----------------

This means,

\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\

is the solution with the initial condition y(0) = 0.

6 0
3 years ago
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