First, you have to get the equation to the normal form of a line. To do this, you divide both sides by -6 to get $\frac{2}{3} x-4$ . The y-intercept is at -4 and your slope is 2/3. Use this to graph the equation.

3 0

3 years ago

PLSSSSSS HELPPPP......Which equation can be used to find the unknown length, b, in this triangle?

castortr0y [4]

Its A. the side lengths squared equal the hypotenuse squared.

6 0

2 years ago

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Find the volume of the wedge cut from the first octant by the cylinder z=12-3y^2 and the plane x+y=2.

LuckyWell [14K]

Answer:

The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2

0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2

V = ∫∫∫ dzdydx

dz has changed from zero to 12−3y^2

dy has changed from zero to 2-x

dx has changed from zero to 2

V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =

24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20

Step-by-step explanation:

8 0

3 years ago