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Law Incorporation [45]
2 years ago
14

What is the period for tangent functions? (Answer in radians)

Mathematics
1 answer:
prisoha [69]2 years ago
3 0

Answer: 2 radians

Step-by-step explanation: You welcome

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Data Set #1
Harman [31]

Answer:

The data table is attached below.

Step-by-step explanation:

The average of a set of data is the value that is a representative of the entire data set.

The formula to compute averages is:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

Compute the average for drop 1 as follows:

\bar x_{1}=\frac{1}{3}\times[10+11+9]=10

Compute the average for drop 2 as follows:

\bar x_{2}=\frac{1}{3}\times[29+31+30]=30

Compute the average for drop 3 as follows:

\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33

Compute the average for drop 4 as follows:

\bar x_{4}=\frac{1}{3}\times[102+100+98]=100

Compute the average for drop 5 as follows:

\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67

The data table is attached below.

3 0
2 years ago
Which transformation of a scalene triangle produces an image that is similar, but not congruent, to the original?
melisa1 [442]
I'm guessing dilation of magnitude 6 centered at the origin
5 0
3 years ago
I need help with my math homework. <br> Find the slope of each line.<br> Thanks!
guajiro [1.7K]
7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4
6 0
2 years ago
PLEASE HELP!!! I ONLY HAVE A FEW MINUTES!!
TEA [102]

Answer:

y=0.25x-6

Step-by-step explanation:

6 0
2 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
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