Answer: f(x) = 3x^(2)-2x+1
f(x) = 3x^(2)-2x+1 = y-intercept (0, 1).
g(x) = -10x^(2)+50x = y-intercept (0, 0).
As we see, the first equation (f(x) = 3x^(2)-2x+1) has a y-intercept of (0, 1), while the other equation (g(x) = -10x^(2)+50x) has a y-intercept of (0, 0). This means that the quadratic equation that has the greatest y-intercept is f(x) = 3x^(2)-2x+1, which is (0, 1).
Step-by-step explanation:
Hope this helps =)
