Answer:
Amount of excess Carbon (ii) oxide left over = 23.75 g
Explanation:
Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
Molar mass of Fe₂O₃ = 160 g/mol;
Molar mass of Carbon (ii) oxide = 28 g/mol
From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g) of carbon (ii) oxide
450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide
Therefore the excess reactant is carbon (ii) oxide.
Amount of excess Carbon (ii) oxide left over = 260 - 236.25
Amount of excess Carbon (ii) oxide left over = 23.75 g
Answer:
Volume of NCl3 is 3L
Explanation:
Avogadro states: All gases at the same volume under temperature and pressure constant have the same number of moles.
The chemical equation is:
3Cl2(g) + N2(g) → 2NCl3(g)
Where 3 moles of chlorine reacts with 1 mole of nitrogen to produce 2 moles of NCl3.
But using Avogadros law we can say:
3L of chlorine and 1L of nitrogen produce 2L of Nitrogen trichloride.
3L of chlorine and 1L of nitrogen: 4L (The stoichiometric mixture)
That means, volume of NCl3 produced is 3L
Graduated cylinders have numbers on the side that help you determine the volume<span>.</span>
A mole is equal to 6.02x10^23, so one mole of H2O has 6.02x10^23 water molecules. To get how many of them are in 6 moles you need to multiple it by six:
(6.02x10^23)x6= 3.612x10^24
So, there’s 3.612x10^24 water molecules in 6 moles of water
