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3 years ago

Branches are thrown into a wood chipper and mulch is created. Chemical change or physical change?

Chemistry

1 answer:

murzikaleks [220]3 years ago

5 0

Answer:

it's a physical change

Explanation:

there there was no burning it was grabbing and just cutting

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15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th

Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

Explanation:

For N2,

Pressure(P₁)=125 kPa

Volume(V₁)=15·1 L

Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

Pressure(P₂)= 125 kPa

Volume(V₂)= 44.3 L

Temperature(T₂)=25°C= 298 K

Then, for the mixture,

Volumeof the mixture( V)= 6.25 L

Pressure(P)=?

Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

$\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

or, $6.34+18.58=\frac{P*6.25}{324}$

or, $P=\frac{24.92*324}{6.25}$

∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

3 0

2 years ago

Why phosphorus forms 3 bonds in molecule such as PH3 and PCl3-

gregori [183]

Phosphorous has three lone electrons that need pairing. Similar to how carbon has 4 lone electrons, and forms CH4

6 0

3 years ago

Read 2 more answers

How does the sun impact the speed of the water cycle?

IceJOKER [234]

the sun makes it evaporate quicker if it is there for longer

8 0

3 years ago

How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?

vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0

3 years ago

If a class has 120 students and the professor wants to purchase two cookies per student (or 2 coo/stu) he or she will need to bu

klio [65]

60 just divide 120 by 2

7 0

2 years ago