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andrey2020 [161]
2 years ago
15

3x + 2y = 8 5x + 2y = 12

Mathematics
1 answer:
Keith_Richards [23]2 years ago
5 0

Answer:

Step-by-step explanation:

We can solve this in either of two ways.  I'll do both.

<u>Mathematically</u>

3x + 2y = 8

5x + 2y = 12

Rewrite either equation to isolate y.  I'll use

3x + 2y = 8

2y = 8 - 3x

y = (8-3x)/2

Now use this value of y in the other equation:

5x + 2y = 12

5x + 2((8-3x)/2) = 12

5x + (8 - 3x) = 12

2x = 4

x = 2

Use x=2 to find y:

y = (8-3x)/2

y = (8-3*(2))/2

y = (8-6)/2

y = 1

The point is (2,1)

<u>Graphically</u>

Graph the two equations and find the point they intersect.  See attachment.  

We obtain the same answer:  (2,1)

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Step-by-step explanation:

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insens350 [35]
The line 6x - 2y = 12 goes through -6 on the y-axis and 2 on the x-axis ie through (0, -6) and (2, 0)
The line will be solid and shaded above (towards the origin)

There are an infinite number of choices for the example points!
Here is my selection.
(0, 0) is in the solution set. 6 x 0 - 2 x 0 = 0 which is less than 12
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3 years ago
Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!
vovikov84 [41]

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

5 0
3 years ago
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