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2 years ago

Pls show steps on how to do it

Mathematics

2 answers:

qwelly [4]2 years ago

7 0

Step-by-step explanation:

½× 10 × 5√3 cm² =

25√3 cm²

43.30 cm²

Mariana [72]2 years ago

5 0

<h2>>> Answer </h2>

_________

$\:$

1/2 × 10 × 5 $\sqrt{3}$ = ...

= 5 × 5 $\sqrt{3}$

= 25 $\sqrt{3}$

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Last year, liliana earned

olga_2 [115]

Answer:

$376,528

Explanation: You have to ÷ $4,518,336 by 12 because there is 12 months in 1 year. That equals 376,528. Therefore her average income was $376,528.

3 0

4 years ago

15 divided by 84 i need the answer now

Bingel [31]

Answer:

0.1785

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

HELP ASAP WILL MARK BRAINLIEST

DochEvi [55]

Answer:

EF , HG , Parallel

Step-by-step explanation:

Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.

Also given that AB was parallel to DC.

Now we have to fill in the certain blanks.

Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.

Also HG is parallel to DC, EFGH is a translated image of ABCD.

Also we are given that AB is parallel to DC. Hence we have following results.

AB║DC

AB║EF

Hence CD║EF

also

CD ║HG

CD║EF

Hence we can come to conclusion that

EF║HG

Hence our answer will be

corresponding segments EF and HG are parallel to each other.

3 0

3 years ago

2. Tina uSUally brings her children every Sunday afternoon at the children's park in their barangay. The park is 350m Iong and 2

Verdich [7]

Answer: kindly check explanation

Step-by-step explanation:

Given the following :

Total area of parknand path way = 74,464 m2.

Dimension of park = 350m by 200m

Using the area of rectangle formula:

Area = Length * width

Area of park = 350m * 200m

Area of park = 70,000

Area of path = (74,464 - 70,000) = 4,464m2

Since path has uniform width, then width of the the path is sqrt(4464) = 66.8m

2.) the path of the park seems a bit narrow, hence, I wouldn't love children to bike and jog in such a narrow path

4 0

4 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago