3. g(x) = (x+2)/ |x+2| the denominator cannot be 0
|x+2| cannot be 0
x cannot equal -2
Domain all real numbers but -2
g(-1) = (-1+2)/ |-1+2| = 1/|1| = 1
4. h(x) = (x-4)/(x^2+5x-36)
factor the denominator
h(x) = (x-4)/(x+9) (x-4) the denominator cannot be zero do not cancel, this is a hole
x+9 cannot equal zero so x cannot equal -9
x-4 cannot equal 0 so x cannot equal 4
Domain all real numbers but -9 and 4
h(-1) = (-1-4)/((-1)^2+5(-1)-36) = -5/(1-5-36) = -5/-40 = 1/8
Answer:
a^2-ab+3ab^2-2b^2
Step-by-step explanation:
-2a^2b+a^2-5ab+3ab^2-b^2+2(a^2b+2ab)
Open parenthesis
-2a^2b+a^2-5ab+3ab^2-2b^2+2a^2b+4ab
Add
-2a^2b+2a^2b=0
We have
a^2-5ab+3ab^2-2b^2+4ab
Add
-5ab+4ab=-ab
We have
a^2-ab+3ab^2-2b^2
Answer:
5/6
Step-by-step explanation:
1/3 x 2/2 = 2/6
1/2 x 3/3 = 3/6
2/6 + 3/6 = 5/6
Answer:

Step-by-step explanation:


Can I have the brainliest please?
Image below, rotation for point (5,-2) gives you (2,5).