It is A) 1,482 cm3 ..............
Answer:also confused ?
Explanation:cant see full answer
Once you balance the enquation you "switch partners" of the element (negative charge to positive charge)
The masses of CO and CO2 are 90.55g and 100−90.55=9.45 g respectively.
<h3>Total mass.</h3>
Let the mixture has 100g as total mass.
The number of moles of CO is 2890.55=3.234.
The number of moles of CO2 is 449.45=0.215.
The mole fraction of CO is 3.234+0.2153.234=0.938.
The mole fraction of CO2 is 1−0.938=0.062.
The partial pressure of CO is the product of the mole fraction of CO and the total pressure.
It is 0.938×1=0.938 atm.
The partial pressure of carbon dioxide is 0.062×1=0.042 atm.
The expression for the equilibrium constant is:
Kp=PCO2PCO2=0.062(0.938)2=14.19
Δng=2−1=1
Kc=Kp(RT)−Δn=14.19×(0.0821×1127)−1=0.153.
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The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.
<h3>How do we calculate molar mass?</h3>
Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.
Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:
Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)
Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.
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